;t = c * r
;
;c = k/v
;r = v/i
;t = k/v * v/i = k/i
;
;i = k/s
;t = k / k/s = s
;
;so, time to dis|charge a capacitor within 0-63%-0
;with given resistance r and capacitance c
;equals t=c*r seconds

;e.g.:
c = 5    * 10^(-9)
r = 0.95 * 10^0
t = c*r

second = 1
freq = second/(2*t) ; ~ 105.2 FM :)
